Answer: Rs. 2206.75
Solution:
By using direct formula of simple interest:\(SI=\frac{PTR}{100}\)
P=14000 R=?, T=3,SI=Rs 2100 by solving we will get R=5%
Now use \(Amount=P(1+\frac{R}{100})^n\)
Use R=5% then we will get A= Rs. 16206.75
compound interest=A-P =16206.75-14000=Rs. 2206.75, so the compound interest earned=Rs. 2206.75
Answer: Rs.520
Solution:
SI for first 6 years : P----130
SI for next 6 years for triple of principal amount: 3P------390
Total interest end of 12th year :-----520
so, the answer is: RS 520
Answer: Rs 2520
Solution: Principal (here, the amount) = Simple Interest x 100/ Rate x Time = 1575 x 100/5 x 12.5 = Rs.2520. Ans.
Answer: 2 yrs
Solution:
By using direct formula of simple interest:\(SI=\frac{PTR}{100}\)
P=1000 R=7%, SI=140,T=? by solving we will get 2 Years
Answer: Rs. 750
Solution:
SI for first 6 years : P----250
SI for next 6 years for double of principal amount: 2P------500
Total at the end of 12th year : ------750
so, the answer is: RS 750
Answer: Rs.1200
Solution:
SI for 10 years is: Rs. 600
SI for first 5 years : P----300
SI for next 5 years for triple of principal amount: 3P------900
Total interest end of 10th year :-----300+900=1200
so, the answer is: RS 1200
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Answer: Rs.800
Solution: We have interest for fifth year as 1200 – 1120 = Rs. 80 Since interest is same for all the years Hence, we can say that interest for 4 years will be 80 × 4 = 320 Hence, amount at the starting of time = 1120 – 320 = Rs. 800