Answer: 10
Solution:
let the principal amount=P, Rate of Interest=R% and Time=5 years
Then amount= \(2P=P(1+\frac{R}{100})^5\)
let for n years the amount will be 4 times then
\(4P=P(1+\frac{R}{100})^n\)
From the above 2 equations we get \(2^\frac{n}{5}=2^2\) by solving we will get n=10
so answer is 10 years
Answer: 17280
Solution:
let the principal amount be P=50000, R=16%, n=2 years, A=?
Now use \(A=P(1+\frac{R}{100})^n\)
we will get A=67280, so the Compound interest= A-P=67280-50000=Rs.17280
Answer: 6250
Solution:
6250
Answer: 2
Solution:
let the principal amount be P=800, R=5%, n=?, A=882
Now use \(882=P(1+\frac{R}{100})^n\)
we will get n=2, so the answer is 2 years
Answer: rs.2500
Solution:
Rs.2500
Answer: 4000
Solution:
4000
Answer: 4600
Solution:
By using the direct formula of simple interest:\(SI=\frac{PTR}{100}\)
let the principal amount be P, R=10%, T=2, SI=? by solving we will get SI=0.20P
Now use \(Amount=P(1+\frac{R}{100})^n\)
Use R=12% then we will get A
compound interest=A-P =A-P=0.21P
Difference of SI and compound interest is Rs.72
therefore 0.21P-0.20P=46, from this P=Rs. 4600
Answer: 10190
Solution:
let the principal amount be P=20480, R=20%, n=2 years 73 days=2\(\frac{1}{5}\), A=?
Now use \(A=P(1+\frac{R}{100})^2*(1+\frac{1/5}{100})\)
we will get A=30670, so the Compound interest= A-P=30670-20480=Rs.10190
Answer: 425
Solution:
425
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Answer: 7200
Solution:
By using the direct formula of simple interest:\(SI=\frac{PTR}{100}\)
let the principal amount be P, R=12%, T=2, SI=? by solving we will get SI=0.24P
Now use \(Amount=P(1+\frac{R}{100})^n\)
Use R=12% then we will get A= 1.25P
compound interest=A-P =1.25P-P=0.25P
Difference of SI and compound interest is Rs.72
therefore 0.25P-0.24P=72, from this P=Rs. 7200