Answer: 0.4
Solution:
Gain of 25% on whole=Gain of 10% of 3000+Gain of x% of 3000
\(\frac{125}{100} *6000= \frac{110}{100} *3000+ \frac{x}{100} *3000\)
7500=3300+30x
x=140
To get a gain of 25% on the whole, he must sell the remainder at 40 percent.
hence answer is 0.4
Answer: 400
Solution:
let the cost of one watch be x and another watch cost be 900-x
one sold at 20% profit i.e \(\frac{120x}{100}=\frac{12x}{10}\)
another one sold at 25% loss i.e \(\frac{75*(900-x)}{100}\)
There is no gain and loss in whole transaction i.e \(\frac{12x}{10}+\frac{75(900-x)}{100}=900\)
by solving above equation we get 500 rupees
but,The CP of the cost in whole transaction on which the shopkeeper losses is 900-x=900-500=400
hence answer is Rs.400
Answer:
Solution:
Answer:
Solution:
Answer: 20%
Solution:
Let the cost price of 1set sofa=CP1=500
and cost price of 2nd set=CP2=300
The profit percentage he made on second set twice the (Numerical value) loss made on the first set.
i.e SP2-CP2=2(CP1-SP1) where SP1 and SP2 are selling prices of first and second set
=> SP2+2SP1=1300 ----------------i
In entire transaction the trader make gain of 2.5%. What is loss percentage on the first set
SP1+SP2=\(\frac{112.5}{100}*(500+300) =900\)
=> SP1+SP2=900 --------------ii
by solving equation i and ii we get SP1=400 and SP2=500
so, the loss on first set= \(\frac{500-400}{500}*100 =20 %\)
Answer:
Solution:
Answer: Rs. 9.1666 per kg
Solution:
given 100 kg rice=1100
then 1 kg rice= Rs 11, i.e cost price per kg
The loss for 20 kg rice
loss(%)=\(\frac{20*S.P}{100}=C.P-S.P\)
1/5(s.p)=11-s.p
by solving S.P=55/6 =9.166 per kg
Answer: Rs.300
Solution:
for a loss of 15% \(\frac{85}{1000}*C.P=204\)
\(\Rightarrow C.P=240\)
At a profit of 25%, \(\frac{125}{100}*240=300\)
hence he should sold at Rs. 300 to get a profit of 25%
Answer: 50%
Solution:
LCM of 16 and 12 is 48
C.P of 16 fruits= Rs.24
C.P of 48 fruits =(48/16)x24= Rs.72
S.P of 12 fruits= Rs.27
S.P of 48 fruits =Rs.108
profit%= (108-72)/72 X100 =50%
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Answer: Rs 500
Solution:
let the cost price be X, then 20% of X =1100 i.e \(\frac{20}{100}*x=1100\)
by solving we will get x=5500,
so, Cost price=5500, expenditure on repairs=10%
Actual price=\(\frac{100}{110}*5500= 5000 \)
hence the expenditure on repairs=5500-5000=Rs.500