Q.A can do a work in 24 days. B can do it in 32 days. C can do it 60 days. They start working together and A left after 6 days and B left after working for 8 days. How many more days are required to complete the whole work?
A) 30
B) 25
C) 22
D) 20
Related Questions
Q.
A and B undertook to do a piece of work for Rs. 4500. A alone could do it in 8 days and B alone in 12 days. With the assistance of C, they finished the work in 4 days. C’s share of money is:
A) Rs. 375
B) Rs. 750
C) Rs. 1500
D) Rs. 2250
Q.
A and B can complete a piece of work in 12 days and 18 days respectively. A being to do the work and they work alternately one at a time for one day each. The whole work will be completed in
A) 43/3 days
B) 47/3 days
C) 49/3 days
D) 56/3 days
Q.
A man, a woman and a boy together complete a place of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman take to complete the work?
A) 9 days
B) 21 days
C) 24 days
D) 27 days
Today's Challenging Question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none 1 members solved
Solve Challenging question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none
Correct Answer: 22
Solution:
Work was done by A in 1 day = 1/24
Work was done by B in 1 day = 1/32
Work was done by C in 1 day = 1/60
Work done by A, B and C together in 1 day = 1/24 + 1/32 + 1/60 = 43/480
After 6 days, A leaves.
So, work done by A, B and C together in 6 days = 43/80
Now, B and C work together for the next two days before B leaves.
Work done by B and C together in 1 day = 1/32 + 1/60 = 23/480
So, work done by B and C together in 2 days = 46/480 = 23/240
Work remaining after A and B leaves = 1 - (43/80 + 23/240) = 1 - 152/240 = 88/240 = 11/30
So 11/30 of the work is remaining for C to do alone.
C completes 1 work in 60 days
So, C completes 11/30 of the work in 11/30 * 60 days = 22 days