Q.John can do a piece of work in 24 days. Shawn.in18 days and Kurt in 12 days. If John is assisted by Shawn on one day & by Kurt on next day alternately work will be completed in
A) 8.5 days
B) 80/9 days
C) 82/9 days
D) 9 days
Related Questions
Q.
A and B undertook to do a piece of work for Rs. 4500. A alone could do it in 8 days and B alone in 12 days. With the assistance of C, they finished the work in 4 days. C’s share of money is:
A) Rs. 375
B) Rs. 750
C) Rs. 1500
D) Rs. 2250
Q.
A and B can complete a piece of work in 12 days and 18 days respectively. A being to do the work and they work alternately one at a time for one day each. The whole work will be completed in
A) 43/3 days
B) 47/3 days
C) 49/3 days
D) 56/3 days
Q.
A man, a woman and a boy together complete a place of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman take to complete the work?
A) 9 days
B) 21 days
C) 24 days
D) 27 days
Today's Challenging Question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none 1 members solved
Solve Challenging question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none
Correct Answer: 82/9 days
Solution:
Here let John's 1-day work A=1/24, Shawn 1 day work B=1/18 and Kurt 1 day work C=1/12
John(A) is assisted by Shawn(B) on one day & by Kurt(C) on next day alternately, so
Work was done in first two days i.e (A+B) 1-day work +(A+C) 1-day work
=1/24+1/18+1/24+1/12=4/18=2/9
Work done in 4 pairs(8 days) =2/9×8/2=8/9
Remaining work =1-8/9=1/9
Now, it is the turn of A and B,
∴ (A + B)’s 1 day’s work
=1/24+1/18=7/72
∴ Remaining work =1/9-7/72=1/72
Now, it is the turn of A and C,
∴ (A + C)’s 1 day’s work
=1/24+1/12=3/24
∴ Times taken to complete the remaining work =1/72*24/3=1/9 days
Total time =(8+1+1/9)=82/9 days