Q.The product of two numbers is 2028 and their HCF is 13, the number of such pairs is
A) 1
B) 2
C) 4
D) 3
Related Questions
Q.
The sum of two numbers is 45, their difference is 1/9 of their Sum, their LCM is
A) 200
B) 250
C) 100
D) 150
Q.
The LCM of two numbers is 20 times their HCF. The sum of HCF and LCM is 2520. if one number is 480, the other number is
A) 400
B) 480
C) 520
D) 600
Q.
The HCF of two numbers is 23 and the other two factors of their LCM are 13 and 14, the larger of the two numbers is
A) 276
B) 299
C) 345
D) 322
Today's Challenging Question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none 1 members solved
Solve Challenging question
Q.
Ajay & Bimal can do a price of work in 10 days, Bimal & Chetan can do in 15 days and Chetan and Ajay in 20 days. They work together for 6 days and then Ajay leaves and now Bimal & Chetan work together for 4 more days. If Bimal leaves, how long will Chetan take to finish the work?
A) 12 days
B) 10 days
C) 16 days
D) none
Correct Answer: 2
Solution:
Here HCF=13, let the numbers be 13x and 13y where x and y are prime to each other.
now 13x*13y=2028
=>.xy=12
The possible pairs ae (1,12), (3,4),(2,6)
But 2 and 6 are co-primes. so, the required no. of pairs=2